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Sandy lives 200 m from school. One

morning she leaves for school at a
slow pace. On the way she meets a
friend and stops to talk for 10
minutes. Sandy realizes that she
forgot her homework and runs back
home to pick it up. It takes five
minutes to get home. Immediately she
heads back to school at a fast pace.

User Leo Letto
by
4.9k points

1 Answer

1 vote

Answer:

Following are the solution to the given question:

Explanation:

For question 1:

Calculating the speed between A and B:


Time\ (t)= 1 \ hours\\\\Distance\ (d)= 10 \ km\\\\V=(d)/(t)=(10)/(1)= 10 \ kmph

For question 2:

Calculating the speed between B and C:


Time\ (t)= (2-1)=1 \ hours\\\\Distance\ (d)= (15-10)= 5\ km\\\\V=(d)/(t)=(5)/(1)= 5 \ kmph\\

For question 3:

In this the speed between A and B is the double to speed between B and C.

Sandy lives 200 m from school. One morning she leaves for school at a slow pace. On-example-1
User Ofiris
by
4.8k points