Answer:
Explanation:
Remark
The cos(60) = 1/2
The radii marked 6 is the adjacent side. You have to solve for the hypotenuse.
Why?
Because the hypotenuse is the distance from the center of the circle to the point of intersection of the angle. Once you have the hypotenuse, you can find the length of the tangent, which will lead to the area of the kite. Then take away 1/3 the area of the circle.
Hypotenuse
Cos(60) = 1/2
cos(60) = adjacent / hypotenuse Multiply both sides by the hypotenuse
hypotenuse * cos(60) = adjacent Divide by Cos(60)
hypotenuse = adjacent / cos(60)
adjacent = 6
hypotenuse = 6/0.5
hypotenuse = 12
Tangent
tangent^2 = 12^2 - 6^2
tangent^2 = 144 - 36
tangent^2 = 108
tangent = sqrt(108)
tangent = 6sqrt(3)
Triangles
The area of the triangle = 1/2 6sqrt(3) * 6
The area of the triangle = 18 sqrt(3)
There are two triangles so the area = 36 sqrt(3) That's the area of the kite.
Circle sector.
Area of the circle sector = 1/3 * pi * r^2
r = 6
Leave pi as it is.
Area of the circle sector = 1/3 * pi * 6^2
area of the circle sector = 12 pi
Answer
Area of the red part = area of the triangles - the area of circle sector
Area of the red part = 36*sqrt(3) - 12* pi