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Which is the minimum or maximum value of the given function?
dndnsn

1 Answer

2 votes

Answer:

See explanation

Explanation:

The question is incomplete, as the function is not given. So, I will make an assumption.

A quadratic function is represented as:


f(x) = ax^2 + bx + c

If
a > 0, then the function has a minimum x value

E.g.
f(x) = 4x^2 - 5x + 8 ------
4 > 0

Else, then the function has a maximum x value

E.g.
f(x)= -4x^2 -5x + 8 ----
-4 < 0

The maximum or minimum x value is calculated using:


x = -(b)/(2a)

For instance, the maximum of
f(x)= -4x^2 -5x + 8 is:


x = -(-5)/(2*-4)


x = -(5)/(8)

So, the maximum of the function is:


f(x)= -4x^2 -5x + 8


f(-(5)/(8)) = -4 * (-(5)/(8))^2 - 5 *(-(5)/(8)) +8


f(-(5)/(8)) = 9.5625

User Henrikmerlander
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