Answer:
The gravitational acceleration in the surface of the moon is 1.63 m/s^2
Step-by-step explanation:
The gravitational acceleration at a distance R of an object of mass M, is given by:
g = G*M/R^2
Where:
G is the gravitational constant.
G = 6.67*10^(-11) m^3/(kg*s^2)
We could think that all the mass of the moon is at its center, then at the surface of the moon, the distance will be equal to the radius of the moon, thus:
R = 1740km
But we want to work with meters, so remember that:
1km = 1000m
then:
1740km = (1740)*1000m = 1740000m
R = 1740000m
And the mass is just:
M = 7.4x10^22 kg
If we input all that in the gravitational acceleration equation, we get:
g = (6.67*10^(-11) m^3/(kg*s^2))*(7.4x10^22 kg)/( 1740000m)^2
g = 1.63 m/s^2
The gravitational acceleration in the surface of the moon is 1.63 m/s^2