9514 1404 393
Answer:
14.71°
Explanation:
The tangent relation can be helpful here.
Tan = Opposite/Adjacent
With reference to the attached diagram ...
tan(22°) = CD/DA = (150 ft)/DA
tan(x) = CD/DB = (150 ft)/(DA +200 ft)
Substituting for DA, we find ...
tan(x) = (150 ft)/((150 ft)/tan(22°) + 200 ft) ≈ 150/(371.26 +200) ≈ 0.262576
x = arctan(0.262576)
x ≈ 14.71°