203k views
1 vote
Cyril has six more than twice as many mangoes as Kubie and half as many mangoes as Maxine. If Kubie has six mangoes, then, in terms of x, how many mangoes do Cyril, Kubie, and Maxine have combined?​

User Valorkin
by
8.3k points

1 Answer

4 votes

Answer:

(7x + 18) or 60 Mangoes

Explanation:

Let the no. of mangoes Kubie possesses be x

So,

Cyril has mangoes = 2x + 6 ...(i)

So,

Maxine has = 2 * (2x + 6)

= 4x + 12

Given that,

Kubie has mangoes = 6

∵ The combined mangoes they have in terms of x,

= Cyril + Kubie + Maxine

= (2x + 6) + x + (4x + 12)

= 7x + 18

A.T.Q.

Cyril has = 2x + 6

∵ Cyril has mangoes = 2 * (6) + 6

= 18 mangoes

∵ Maxine has = 2 * Cyril's mangoes

= 2 * 18

= 36

Thus,

Total mangoes = Cyril + Kubie + Maxine

= 18 + 6 + 36

= 60 Mangoes

User Jeffreyveon
by
8.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories