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Please help, I really need this

Please help, I really need this-example-1

1 Answer

3 votes

9514 1404 393

Answer:

(a) -- the correct choice is highlighted

Explanation:

The units of specific heat tell you what quantities make up the ratio.


\frac{390\text{ J}}{1\text{ kg$\cdot^\circ$C}}=\frac{-12.0\text{ J}}{0.012\text{ kg}\cdot\Delta T}\\\\\Delta T=(-12.0)/(0.012\cdot390)\ ^\circ\text{C}\approx-2.56\text{ $^\circ$C}

The temperature will decrease by 2.56 C.

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