No idea how to do (4r + 20)/(r + 5) when r ≠ 5 ?

Question

No idea how to do


`(4r + 20)/(r + 5)`

when r ≠ 5 ?

Answer 1

Factorize the numerator:

4r + 20 = 4r + 4×5 = 4 (r + 5)

I think you meant to say r ≠ -5, which means r + 5 ≠ 0, so that the denominator is never zero and so the expression is defined (no division by zero). This lets you cancel the factor of r + 5 in the numerator with the one in the denominator:

(4r + 20)/(r + 5) = 4 (r + 5)/(r + 5) = 4