Question

What is the standard form of an equation of the line going through the points K(6,4) and L(-6,4)

Answer 1

y = 4

Explanation:

x1 y1 x2 y2

6 4 -6 4

(Y2-Y1) (4)-(4)= 0 ΔY 0

(X2-X1) (-6)-(6)= -12 ΔX -12

slope= 0

B= 4

Y =0X +4