Given:
The function is:
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To find:
The range of the function.
Solution:
We have,
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It can be written as:
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
Add and subtract square of half of coefficient of x, i.e.,
.
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


On comparing this equation with
, we get
, it means the graph of the function is a downward parabola and the vertex is the point of maxima.


The vertex of the function is (-3,4). So, the value of the function cannot be greater than 4.
Therefore, the range of the function is all real numbers less than or equal to 4.
Note: All options are incorrect.