Answer:
B
Explanation:
Given
2x³ + 16 ← factor out 2 from each term
= 2(x³ + 8) ← x³ + 8 is a sum of cubes and factors in general as
a³ + b³ = (a + b)(a² - ab + b²) , then
x³ + 8
= x³ + 2³
= (x + 2)(x² - 2x + 2²)
= (x + 2)(x² - 2x + 4)
Then
2x³ + 16 = 2(x + 2)(x² - 2x + 4) ← in factored form → B