Question

Find all real and non-real roots of the function ƒ(x) = x2 + 49. Question 1 options: A) x = –7, 7 B) x = –7i, 7i C) x = –49i, 49i D) x = i + 7, i – 7

Answer 1

x = –7i, 7i

Explanation:

Answer 2

Given:

The function is:

`f(x)=x^2+49`

To find:

The all the real and non-real roots of the given function.

Solution:

We have,

`f(x)=x^2+49`

For roots,
`f(x)=0`,

`x^2+49=0`

`x^2=-49`

Taking square root on both sides, we get

`x=\pm √(-49)`

`x=\pm √(-1)√(49)`

`x=\pm 7i`
`[\because √(-1)=i]`

The roots of the given function are -7i and 7i.

Therefore, the correct option is B.