Question

Pls help

The equation of a line parallel to 6x – 2y + 10 = 0 and passes through the point
(-2,7).

Answer 1

Y = 3X + 13

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

6x - 2y + 10 = 0 ( subtract 6x + 10 from both sides )

- 2y = - 6x - 10 ( divide terms by - 2 )

y = 3x + 5 ← in slope- intercept form

with slope m = 3

Parallel lines have equal slopes , so

y = 3x + c ← is the partial equation

To find c substitute (- 2, 7 ) into the partial equation

7 = - 6 + c ⇒ c = 7 + 6 = 13

y = 3x + 13 ← equation of line in slope- intercept form

Answer 2

y=3x-1

Explanation:

• First we need to rewrite 6x-2y+10 =0 into the standard slope form of y=mx+b when done you get y=3x+5
• Next we need an equation that passes through the point (-2,7). Now remember equations that are parallel have the same slope so the equation should look like y=3x
• In standard slope form the b is the y-intercept. We now need to plug in the x ordered pair value into the standard slope equation. y=3(-2)+5 to get y=-1 meaning -1 is the y-intercept
• Therefore the answer is y=3x-1