Question

A body starts with an initial velocity of 15m/s and accelerates 4m/s2. Find the distance covered by 5s

Answer 1

Distance, S = 110 meters

Step-by-step explanation:

Given the following data;

Initial velocity = 15 m/s

Acceleration = 4 m/s²

Time = 5 seconds

To find the distance covered, we would use the second equation of motion;

`S = ut + (1)/(2) at^(2)`

Where;

S is the distance covered or displacement of an object.

u is the initial velocity.

a is the acceleration.

t is the time.

Substituting the values into the equation, we have;

`S = 15*4 + (1)/(2) * 4*5^(2)`

`S = 60 + 2*25`

`S = 60 + 50`

Distance, S = 110 meters