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If a thin rod of platinum is placed in an external magnetic field of 1.2000 T, with its axis parallel to that field, what will be the magnetic field inside the rod?

1 Answer

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Answer:


B_1=1.29967T

Step-by-step explanation:

From the question we are told that:

Relative permeability Platinum
\mu= 1.00026

Magnetic field
B_e= 1.3000 T

Generally the equation for Magnetic field is mathematically given by


B_i=(B_e)/(\mu)


B_i=(1.3)/(1.00026)


B_1=1.29967T

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