How many liters of a 10% alcohol solution must be mixed with 40 liters of a 50% alcohol solution to obtain a 40% alcohol solution?

asked Apr 28, 2022 106k views

2 votes

How many liters of a 10% alcohol solution must be mixed with 40 liters of a 50% alcohol

solution to obtain a 40% alcohol solution?

5.9k points

Please log in or register to add a comment.

2 votes

Answer:

13
(1)/(3)

Explanation:

$20+.1x=.4\left(40+x\right)$

x=40/3 = 13
(1)/(3)

Jimsweb answered May 2, 2022

6.4k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

6.5m questions

8.7m answers