Question

- Mean test score was 200 with a standard deviation of 40- Mean number of years of service was 20 years with a standard deviation of 2 years.In comparing the relative dispersion of the two distributions, what are the coefficients of variation

Answer 1

The correct answer is "Test 20%, Service 10%".

Explanation:

As we know,

The coefficient of variation (CV) is:

⇒
`CV=(Standard \ deviation)/(Mean)* 100`

Now,

CV of test will be:

=
`(40)/(200)* 100`

=
`20` (%)

CV of service will be:

=
`(2)/(20)* 100`

=
`10` (%)