Question

A circle has a radius of 10 units and is centered at (-9,9). What is the equation of this circle? \sqrt{9

square root of, 98, end square write the equation of this circle.

Answer 1

A circle has an equation of a form,

`(x-a)^2+(y-b)^2=r^2`

Where
`(a, b)` is the center and
`r` is the radius.

The coordinates of your circle center are
`(a,b)=(-9,9)` and the radius is
`r=√(98)`, so plug that in,

`(x-(-9))^2+(y-9)^2=√(98)^2`

and simplify to get the equation,

`(x+9)^2+(y-9)^2=98`

Hope this helps :)