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Question 13 of 46
What is the remainder for the synthetic division problem below?

Question 13 of 46 What is the remainder for the synthetic division problem below?-example-1
User Jhkuperus
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1 Answer

4 votes

Answer:

Explanation:

Let's do this out as best as we can here. Here's the problem:

2 | 3 1 2 -7

___________

The rule is to bring down the first term, whatever it is (ours is a 3), and multiply it by the number "outside" which is a 2. Put that product up under the number next to the 3:

2 | 3 1 2 -7

6

3

Then add straight down, and multiply that sum by the 2 outside and put that product under the next number (the 2 "inside" the box):

2 | 3 1 2 =7

6 14

3 7

And do the same thing. Add straight down, multiply the sum by 2 and put the product up under the next number, -7, and add again. The final is shown below:

2 | 3 1 2 -7

6 14 32

3 7 16 25

The last number in the very bottom row, the depressed polynomial row, is the remainder. Ours is a 25. This is the super easy way to divide polynomials, as long as our divisor is a linear (first degree) term.

User Douglas Held
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