Question

I need help solving this please
Trigonometry

Answer 1

11. x = 32.6°

12. x = 27.0

Explanation:

Question 11

`\sin(\theta)=\frac{\textsf{opposite side}}{\textsf{hypotenuse}}`

Given:

• 
  `\theta` = x
• side opposite angle = 7
• hypotenuse = 13

`\implies \sin(x)=(7)/(13)`

`\implies x=\sin^(-1)\left((7)/(13)\right)`

`\implies x=32.6\textdegree \textsf{ (nearest tenth)}`

Question 12

`\sin(\theta)=\frac{\textsf{opposite side}}{\textsf{hypotenuse}}`

Given:

• 
  `\theta` = 64°
• side opposite the angle = x
• hypotenuse = 30

`\implies \sin(64\textdegree)=(x)/(30)`

`\implies x=30\sin(64\textdegree)`

`\implies x=27.0\textsf{ (nearest tenth)}`