Question

Determine the magnitude as well as direction of the electric field at point A, shown in the above figure. Given the value of k = 8.99 × 1012N/C. where, d= 11 cm Q= 12.5 C

Answer 1

The electric field is 9.3 x 10^12 N/C and the direction is away from the charge.

Step-by-step explanation:

charge, Q = 12.5 C

distance, d = 11 cm = 0.11 m

Let the electric field is E.

`E =(K Q)/(d^2)\\\\E = (9* 10^9* 12.5)/(0.11* 0.11)\\\\E = 9.3* 10^(12) N/C`

The direction of electric filed is away from the charge.