Question

Find the equation of Straight line which passes through the point A(-5,10) makes equal intercept on both axes.

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Answer 1

y = -x + 5

Explanation:

The point is in quadrant 2, so the line must pass through points that look like (a, 0) and (0, a) where a is a positive number. The slope of such a line is -1.

If (x, y) is a point on the line, then the slope between points (x, y) and (-5, 10) is 1, and you can write

`(y-10)/(x-(-5))=-1\\y-10 = -1(x+5)\\y-10=-x-5\\y=-x+5`