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Factorise 2x3+9x2+10x+3

User Ckarabulut
by
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1 Answer

3 votes

Answer:

Hello,

Answer is (x+1)(x+3)(2x+1)

Explanation:


p(x)=2x^3+9x^2+10x+3\\p(-1)=2*(-1)^3+9*(-1)^2+10*(-1)+3=-2+9-10+3=0\\p(x)\ is\ divisible\ by\ (x+1)We\ arrange\ to\ put\ a\ factor\ of\ x+1\\\\2x^3+9x^2+10x+3\\\\=2x^3+2x^2+7x^2+7x+3x+3\\\\=2x^2(x+1)+7x(x+1)+3(x+1)\\\\=(x+1)(2x^2+7x+3)\\\\=(x+1)(2x^2+6x+x+3)\\\\=(x+1)(2x(x+3)+1(x+3))\\\\=(x+1)(x+3)(2x+1)\\

User Simara
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