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An object is thrown from the ground with an initial velocity of 30 m/s. What is the velocity at the point 25 m above the ground?

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Answer:

35

Step-by-step explanation:

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User Gulnaz
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7 votes

Answer:

It's a pretty simple suvat linear projectile motion question, using the following equation and plugging in your values it's a pretty trivial calculation.

V^2=U^2+2*a*x

V=0 (as it is at max height)

U=30ms^-1 (initial speed)

a=-g /-9.8ms^-2 (as it is moving against gravity)

x is the variable you want to calculate (height)

0=30^2+2*(-9.8)*x

x=-30^2/2*-9.8

x=45.92m

User Raduken
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