Question

!PLEASE EXPLAIN IT EASY SO I UNDERSTAND IT!

Elliot has been running a lawn care business since 2000. He cuts grass, trims, and weed whacks yards for his customers throughout the season. Each year, he has increased his fee by the same amount. The table shows what Elliot charged each customer for two given years of his business:


Year Lawn Care Fee
2000 $750
2010 $1350


A. What is the rate of change and initial value for Elliot’s business? How do you know?
B. Write an equation in slope-intercept form to represent the fees that Elliot charges each year.

Answer 1

$1350-$750=$600
2010-2000=10 years
600/10=$60 increase per year
a) since elliot started with $750 in 2000 and he started working in 2000 that would be his initial fee and every year he increased his fee by $60.
b) y=60x+750

Answer 2

Rate of Change: $60 Per year

Explanation:

We can find how many years are from 2000 to 2010 not overcouting. That is 10. Now, we do 1350 minus 750 because that's the change of the fee. That will give you 600. Now, 600 divided by 10, giving you how much change each year. That's 60.

So,

2000:750

2001:810

2002:870

2003:930

2004:990

2005:1050

2006:1110

2007:1170

2008:1230

2009:1290

2010: 1350

You can graph it out with that, now.