Question

The earplug can reduce the sound level to about 18 decibels (dB). What percentage reduction is this intensity?

Answer 1

The change in intensity is 63%.

Step-by-step explanation:

intensity level = 18 db

Let the intensity is I.

Io = 10^(-12) W/m^2

Use the formula of intensity

`dB = 10 log\left ( (I)/(Io) \right )\\\\18 = 10 log\left ( (I)/(Io) \right )\\\\1.8 = log\left ( (I)/(Io) \right )\\\\\left ( (I)/(Io) \right )=63.1`

So, the change in intensity is 63%.

Answer 2

1 x 10 -10 whisper at 1m distance.

Step-by-step explanation:

• Properly fitted ear plugs an reduce noise form 15-30db. Although they are better for low frequency