4x^5/2x^2+5=59 please help

Question

asked Nov 5, 2022 144k views

1 Answer

Kdyz · Answer 1 · 2022-11-09T18:20:47+0000

Answer:

${ \tt{ \frac{4 {x}^(5) }{2 {x}^(2) + 5 } = 59 }}$

Cross multiply the variables:

${ \tt{4 {x}^(5) = 59(2 {x}^(2) + 5)}} \\ { \tt{4 {x}^(5) = 118 {x}^(2) + 295}} \\ { \tt{4 {x}^(5) - 118 {x}^(2) = 295}}$

Factorise the equation:

${ \tt{ {x}^(2)(4 {x}^(3) - 118) = 295 }}$

Either x² or ( 4x³ - 118 ) is equal to 295:

For x²:

${ \tt{ {x}^(2) = 295}} \\ { \tt{first \: answer : \: x =17.2 }}$

For ( 4x³ - 118 ):

${ \tt{4 {x}^(3) = 413 }} \\ { \tt{ {x}^(3) = 103.25}} \\ { \tt{second \: answer : \: x = 4.7 }}$