Question

Consider the reaction below. How much heat is absorbed if 5.00 moles of nitrogen react

with excess oxygen?
2 N2 (8) + O2(g) → 2 N20 (8) AHrxn- +163.2 kJ

Answer 1

Step-by-step explanation:

The given chemical reaction is:

`2 N_2 (g) + O_2(g) -> 2 N_20 (g) delta Hrxn= +163.2 kJ`

When two moles of nitrogen reacts with oxygen, it requires 163.2kJ of energy.

When 5.00 mol of nitrogen requires how much energy?

`5.00 mol x (163.2 kJ )/(2 mol) \\=408 kJ`

Hence, the answer is 408 kJ of heat energy is required.