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(x/a)+(x/b)=c; where a≠0, b≠0, a≠-b, solve for x

(x/a)+(x/b)=c; where a≠0, b≠0, a≠-b, solve for x
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(x/a)+(x/b)=c; where a≠0, b≠0, a≠-b, solve for x

User Obayhan
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Answer:

I hope it is correct.. :)

(x/a)+(x/b)=c; where a≠0, b≠0, a≠-b, solve for x-example-1
User Algold
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