Answer:
m(∠C) = 18°
Explanation:
From the picture attached,
m(arc BD) = 20°
m(arc DE) = 104°
Measure of the angle between secant and the tangent drawn from a point outside the circle is half the difference of the measures of intercepted arcs.
m(∠C) =
![(1)/(2)[\text{arc(EA)}-\text{arc(BD)}]](https://img.qammunity.org/2022/formulas/mathematics/high-school/5cgni7tz6g52xkquxjdmj21cg9l5ck1lsb.png)
Since, AB is a diameter,
m(arc BD) + m(arc DE) + m(arc EA) = 180°
20° + 104° + m(arc EA) = 180°
124° + m(arc EA) = 180°
m(arc EA) = 56°
Therefore, m(∠C) =

m(∠C) = 18°