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Let $f$ be a linear function for which $f(6)-f(2)=12$. What is $f(12)-f(2)?$ Please explain how you found your answer. Thank you!

User Mannykary
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1 Answer

2 votes

Answer: 30

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Step-by-step explanation:

Since f(x) is linear, this means f(x) = mx+b

  • m = slope
  • b = y intercept

Let's plug in x = 6


f(x) = mx+b\\f(6) = m*6+b\\f(6) = 6m+b

Repeat for x = 2


f(x) = mx+b\\f(2) = m*2+b\\f(2) = 2m+b

Now subtract the two function outputs


f(6)-f(2) = (6m+b)-(2m+b)\\f(6)-f(2) = 6m+b-2m-b\\f(6)-f(2) = 4m\\

The b terms cancel out which is very handy.

Set this equal to 12, since f(6)-f(2) = 12, and solve for m


f(6)-f(2) = 12\\4m = 12\\m = 12/4\\m = 3\\

So the slope of f(x) is m = 3

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Next, plug in x = 12


f(x) = mx+b\\f(12) = m*12+b\\f(12) = 12m+b

We can then say:


f(12)-f(2) = (12m+b)-(2m+b)\\f(12)-f(2) = 12m+b-2m-b\\f(12)-f(2) = 10m\\

Lastly, we plug in m = 3


f(12)-f(2) = 10m\\f(12)-f(2) = 10*3\\f(12)-f(2) = 30\\

User Simon Sot
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