Question

Answer the question please

Answer 1

#1.

BD = CE (given)

∠BDC = ∠ CEB (each 90° as BD and CE are altitudes)

BC = BC (common)

#2.

Yes, ∆CBD ≅ ∆BCE

(by RHS congruence)

#3.

Yes, ∠DCB = ∠EBC by [C.P.C.T.]

Answer 2

`\huge \rm{Answer:}`

#1.

BD = CE (given)

∠BDC = ∠ CEB (each 90° as BD and CE are altitudes)

BC = BC (common)

`\\`

#2.

Yes, ∆CBD ≅ ∆BCE

• (by RHS congruence)

`\\`

#3.

Yes, ∠DCB = ∠EBC by [C.P.C.T.]

`_______________________________________________`

`{ \boxed{\underline{ \tt}}}`