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What is the solution of this system of linear equations?

3y = 3 y equals StartFraction 3 over 2 EndFraction x plus 6.x + 6
y – StartFraction one-half EndFraction y minus StartFraction 1 over 4 EndFraction x equals 3.x = 3

User ABcDexter
by
8.5k points

2 Answers

3 votes

Answer:

C. no solution

Explanation:

did it on edge2021

User Mbouclas
by
7.6k points
6 votes

Answer:


x = 4


y = 4

Explanation:

Given


3y = (3)/(2)x + 6


y-(1)/(4)x = 3

Required

The solution

Multiply the second equation by 3


3 * [y-(1)/(4)x = 3]


3y-(3)/(4)x = 9

Rewrite as:


3y =(3)/(4)x + 9

Subtract this from the first equation


[3y = (3)/(2)x + 6]- [3y =(3)/(4)x + 9]


3y - 3y = (3)/(2)x - (3)/(4)x + 6 - 9


0 = (3)/(4)x -3

Rewrite as:


(3)/(4)x =3

Multiply both sides by 3/4


x =3*(4)/(3)


x = 4

Substitute
x = 4 in
3y = (3)/(2)x + 6


3y = (3)/(2) * 4 + 6


3y = 6 + 6


3y = 12

Divide both sides by 3


y = 4

User Boonyongyang
by
8.3k points

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