Answer:
A bag of apples cost $3.2 and orange $1.6
Let oranges be o and apples be a
- o + 3a ↬ 11.2
- 2o + 4a ↬ 16
making o the subject
solve them simultaneously
11.2 - 3a = (16-4a)/2
2(11.2 - 3a) = 16 -4a
22.4 -6a = 16 -4a
2a = 6.4
a = 3.2
➜ Therefore a bag of apples cost $3.2
Find the cost of oranges:
o = 11.2 - 3a
o = 11.2 -3(3.2)
o = 1.6
➜ Therefore a bag of oranges cost $1.6