Answer:
[CO₂] = [NO] ≈ 0.11 mol/dm³
[CO] = 0.25 mol/(25 L) = 0.01 mol/dm³
[NO₂] = 0.45 mol/(25 L) = 0.018 mol/dm³
Step-by-step explanation:
The number of moles of CO = 0.25 moles
The number of moles of NO₂ = 0045 moles
The temperature of the vessel = 350°C
The equilibrium constant, Kc = 67.5
We have;
The product of the the concentration of the products = Kc × The product of the concentration of the reactants, therefore;
[CO₂] × [NO] = 67.5 ×(0.25/25 × 0.45/25) = 0.01215
Given that [CO₂] = [NO], we get;
[CO₂] = [NO] = √0.01215 ≈ 0.11 mol/dm³
[CO] = 0.25 mol/(25 L) = 0.01 mol/dm³
[NO₂] = 0.45 mol/(25 L) = 0.018 mol/dm³