Question

Please help
Me find that last box I’m struggling

Answer 1

• Axis of symmetry: x=2
• Vertex: (2, 8)
• Y-intercept: (0, -4)
• Min/Max: Maximum

Explanation:

Concept:

Quadratic equation formula: y=ax²+bx+c

Axis of symmetry formula=-b/2a

Y-intercept formula=c

Minimum or maximum is determined by the first term of the equation, which is [a]. If [a] is positive, then it is a minimum equation as the parabola heads up. If [a] is negative, then it is a maximum equation as the parabola heads down.

Given:

y = -3x² + 12x - 4

Solve:

The axis of symmetry formula = -b/2a

• -(12)/2(-3) = 2

The Vertex

• y=-3x²+12x-4=-3(2)²+12(2)-4=8
• (2, 8)

Y-intercept=c=(0, -4)

Min/Max

• Since [-3] is negative, it is maximum

Hope this helps!! :)

Please let me know if you have any questions

Answer 2

(0,-4)

Explanation:

To find the y-intercept, substitute x=0

y= -3(0)^2+12(0)-4

=-4