Question

Convert 0.181818 … to a fraction by writing the repeating decimal as an infinite geometric series. Show all of your work (please)

Answer 1

0.181818… = 18 (0.010101…)

… = 18 (0.01 + 0.0001 + 0.000001 + …)

… = 18 (1/100 + 1/100² + 1/100³ + …)

… = 18 (1 + 1/100 + 1/100² + 1/100³ + …) - 18

Then you have

`0.181818\ldots = \displaystyle18\sum_(k=0)^\infty\frac1{100^k} - 18 = \frac{18}{1-\frac1{100}} - 18 = \boxed{\frac2{11}}`