Question

How many moles of magnesium oxide are produced by the reaction of 1.82 g of magnesium nitride with of water

Answer 1

Complete Question

How many moles of magnesium oxide are produced by the reaction of 1.82 g of magnesium nitride with 17.73 g of water? Mg3N2 + 3H20 + 2NH3 + 3MgO

Answer:

`Moles\ of\ MgO = 0.054 mol`

Step-by-step explanation:

From the question we are told that:

Reaction Formula:

`Mg_3N_2 + 3H_2_O => 2NH_3 + 3MgO`

`Mass Mg_3N_2 =1.82g`

`H_20=17.73g`

Therefore

`Moles\ of\ Mg_3N_2 =(1.82g)/(100.25)`

`Moles\ of\ Mg_3N_2 =0.0180 mol`

Generally

`Moles\ of\ H_20 =(17.73g)/(18.015)`

`Moles\ of\ H_20 = 0.9841`

Therefore

`Moles\ of\ MgO =0.0180 mol * (3 mol of MgO)`

`Moles\ of\ MgO = 0.054 mol`

Answer 2

0.0182 mole of magnesium oxide, MgO

Step-by-step explanation:

We'll begin by calculating the number of mole in 1.82 g of magnesium nitride, Mg₃N₂. This can be obtained as follow:

Mass of Mg₃N₂ = 1.82 g

Molar mass of Mg₃N₂ = (3×24) + (2×14)

= 72 + 28

= 100 g/mol

Mole of Mg₃N₂ =?

Mole = mass / molar mass

Mole of Mg₃N₂ = 1.82 / 100

Mole of Mg₃N₂ = 0.0182 mole

Finally, we shall determine the number of mole of magnesium oxide, MgO produced from the reaction. This can be obtained as follow:

Mg₃N₂ + 3H₂O –> 3MgO + 2NH₃

From the balanced equation above,

3 moles of Mg₃N₂ reacted to 3 moles of MgO.

Therefore, 0.0182 mole of Mg₃N₂ will also react to produce 0.0182 mole of MgO.

Thus, 0.0182 mole of magnesium oxide, MgO was obtained from the reaction.