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Use dimensional analysis to solve the following problems. Pay attention to correct use of units and correct use of significant figures in calculations. Please show work!

3) Convert 0.250 moles of aluminum sulfate to grams.

4) Convert 2.70 grams of ammonia to moles.

User Srikanta
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2 Answers

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Answer:

0.000731 grams aluminium sulfate

46.0 mols ammonia

Step-by-step explanation:

ALS = shorthand for aluminium sulfate which has a molar mass of 342.15 g/mol


ALS: (0.250mols)/(1) *(1g)/(342.15mols) = (0.250g)/(342.15)=0.0007307 g

NH3 has a molar mass of 17.031 g/mol


NH3: (2.70g)/(1) *(17.031mols)/(1g) = (0.250g)/(342.15)=45.9837 mols

User Maneesh
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Aluminium sulphate (AlS) whose molar mass is=
\sf{ 342.15(g)/(mol) }

we have to find the 0.250 moles of aluminum sulphate.


\implies AlS=(1g)/(342.15~mole)×0.250~mole \\\\\implies AlS=(0.250)/(342.15)\\\\\implies ((250)/(1000))/((34215)/(100))\\\\\implies (250)/(1000)×(100)/(34215)\\\\=0.00073067\approx{0.0007307~g}


\\\\\\

Ammonia(NH3) whose molar mass is =
\sf{17.031(mol)/(g) }

We have to find 2.70 grams of ammonia


\implies NH_(3)=(17.031~mol)/(1g)×2.70g\\\\ 17.031×2.70\\\\(17031)/(1000)×(270)/(100)\\\\ (4598370)/(100000)\\\\=45.9837\approx{46~mole}

User Robbles
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