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Can someone please solve 3x^2+4x-7<13
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5 votes
Can someone please solve 3x^2+4x-7<13

User Yaakov Belch
by
8.9k points

1 Answer

5 votes

Answer:


-(10)/(3)<x<2\:

Explanation:

Rewrite in standard form:
3x^2+4x-20<0

Factor:
\left(x-2\right)\left(3x+10\right)<0

Solve individually for x:


x-2<0\\x<2


3x+10<0\\3x<-10\\x<(-10)/(3)

Combine:


-(10)/(3)<x<2\:

User Paul Campbell
by
7.8k points
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