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Assume the following potential energies for a Newman projection: anti Me/H or anti Me/Me = 0 kcal/mole; eclipsed H/H = 4 kcal/mole; eclipsed Me/Me = 8 kcal/mole; gauche H/H and gauche H/Me = 0 kcal/mole; gauche Me/Me = 4 kcal/mole For 2,3-dimethylbutane, when drawing a Newman projection viewing down the C2-C3 bond, what is the potential energy of the most stable Newman projection?

User Manolowar
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4 votes

Answer:

0 kcal/mole

Step-by-step explanation:

The most stable Newman projection corresponds to the minimum potential energy: Answer (e) 0 kcal/mole

User Pavel Chernov
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