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Solve h(x)=x^2-2x-8>7

User Abel D
by
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1 Answer

2 votes

Answer:

x < -3 and x > 5

Explanation:

x² - 2x - 8 > 7

~Rewrite in standard form

x² - 2x - 15 > 0

~Factor

(x + 3)(x - 5) = 0

~Solve for both factors

x + 3 = 0

x = -3

x - 5 = 0

x = 5

Best of Luck!

User Shome
by
7.6k points