Answer:
y = -4.9/5.4x - 1.17
Explanation:
First let's convert the equation to standard form of y = mx + b.
4.9x + 5.4y = 3
Subtract 4.9x from both sides.
5.4y = -4.9x + 3
Divide each term by 5.4.
y = -4.9/5.4x + 0.56
If two lines are parallel to each other, they have the same slope slopes.
The first line is y = -4.9/5.4x + 0.56. Its slope is -4.9/5.4. A line parallel/perpendicular to this one will also have a slope of -4.9/5.4.
Plug this value (-4.9/5.4) into your standard point-slope equation of y = mx + b.
y = -4.9/5.4x + b
To find b, we want to plug in a value that we know is on this line: in this case, it is (-3.6, 2.1). Plug in the x and y values into the x and y of the standard equation.
2.1 = -4.9/5.4(-3.6) + b
To find b, multiply the slope and the input of x (-3.6)
2.1 = 3.27 + b
Now, subtract 3.27 from both sides to isolate b.
-1.17 = b
Plug this into your standard equation.
y = -4.9/5.4x - 1.17
This equation is parallel/perpendicular to your given equation (y = -4.9/5.4x + 0.56) and contains point (-3.6, 2.1)
Hope this helps!