9514 1404 393
Answer:
421.4 miles
Explanation:
The flight legs are orthogonal, so the distance can be found using the Pythagorean theorem:
1.2 h × 120 mph = 144 mi
3.3 h × 120 mph = 396 mi
The distance at the end of the second flight leg is ...
d = √(144² +396²) = √177552 ≈ 421.37
The plane is about 421.4 miles from its starting point.
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The heading to its end point is 20° +arctan(3.3/1.2) ≈ 90.02°.