Question

If Cl− is the only anion in the solution, what is the Cl− concentration in milliequivalents per liter?

Answer 1

155mEq/L Cl-

Step-by-step explanation:

A Ringer’s solution contains the following concentrations of cations: 146 mEq/L of Na+, 5 mEq/L of K+, and 4 mEq/L of Ca2+.

As Cl- is the only counterion of those cations:

For Na, the molecule is NaCl and the mEq/L of Cl- = mEq of Na+. The Cl- of the first ion is 146mEq/L Cl-

For K+, The molecule is KCl, mEq Cl- = 5mEq/L Cl-

And, for Ca2+, The molecule is CaCl2 but the equivalents of Ca2+ = Equivalents of Cl- = 4mEq/L Cl-

The total concentration of Cl- are:

146 + 5 + 4 =

155mEq/L Cl-