Question

(6x^2-4x-5)(2x^2+3x)

Answer 1

`\left(6x^2-4x-5\right)\left(2x^2+3x\right)`

`=6x^2\cdot \:2x^2+6x^2\cdot \:3x+\left(-4x\right)\cdot \:2x^2+\left(-4x\right)\cdot \:3x+\left(-5\right)\cdot \:2x^2+\left(-5\right)\cdot \:3x`

`=6\cdot \:2x^2x^2+6\cdot \:3x^2x-4\cdot \:2x^2x-4\cdot \:3xx-5\cdot \:2x^2-5\cdot \:3x`

`=12x^4+10x^3-22x^2-15x`

OAmalOHopeO