Question

bicycle generator rotates at 1800 rad/s, producing an 18.0 V peak emf. It has a 1.00 cm by 3.00 cm rectangular coil in a 0.794 T field. (a) How many turns are in the coil?

Answer 1

N = 42

Step-by-step explanation:

Given that,

Angular velocity,
`\omega=1800\ rad/s`

Peak emf,
`\epsilon=18\ V`

The dimensions of the rectangular coil = 1.00 cm by 3.00 cm

Magnetic field, B = 0.794 T

We know that, the emf of the coil is given by :

`\epsilon=NAB\omega`

Where

N is number of turns in the coil

So,

`N=(\epsilon)/(AB\omega)\\\\N=(18)/(0.01* 0.03* 0.794* 1800)\\\\N=41.98`

or

N = 42

So, there are 42 turns in the coil.