Question

△STR≅△LMN, SR=7b+8, and LN=11b−12. Find b and SR.

Answer 1

Given:

`\Delta STR\cong \Delta LMN`

`SR=7b+8`

`LN=11b-12`

To find:

The value of b and SR.

Solution:

We have,

`\Delta STR\cong \Delta LMN` (Given)

`ST\cong LN` (CPCTC)

`ST=LN`

Substituting the given values, we get

`7b+8=11b-12`

`7b-11b=-8-12`

`-4b=-20`

Divide both sides by -4.

`(-4b)/(-4)=(-20)/(-4)`

`b=5`

Now,

`SR=7b+8`

`SR=7(5)+8`

`SR=35+8`

`SR=43`

Therefore, the value of b is 5 and the measure of SR is 43 units.