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Find the period of the function y = 3/2 tan(1/3^x).

А) pi
B) pi/3
C) 3pi
D pi/6

User Tggm
by
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2 Answers

1 vote
the answer is C 3pi
...
User IUser
by
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5 votes

Answer: 3pi (choice C)

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Step-by-step explanation:

I'm assuming you meant to say

y = (3/2)*tan( (1/3)x )

If so, then that equation is in the form

y = A*tan(Bx)

The B coefficient is B = 1/3 and it directly ties together to the period T.

T = pi/B

T = pi/(1/3)

T = pi*(3/1)

T = 3pi .... answer is choice C

Side note: This formula only works for tangent and cotangent functions.

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