Question

Find the equation of the line perpendicular to y = 3x - 6 that runs through the point (-1, -3).

y
=
1
3
x
+
8
3
y=
3
1
​
x+
3
8
​


y
=
−
1
3
x
−
10
3
y=
3
−1
​
x−
3
10
​


y = -3x + 8

y
=
3
x
+
10
y=3x+10

Answer 1

Explanation:

I'll get you the answer. You pick it from what you are given.

The slope of the perpendicular is m1 * m2 = - 1

m1 = 3

m2 = -1 / m1

m2 = -1 / 3

So far what you have is

y = (-1/3) x + b

Use the point go get b

x = -1

y = - 3

y = (-1/3) *x + b

-3 = (-1/3)*-1 + b

-3 = 1/3 + b

-3 - 1/3 = b

b = -3.33333 or

b = -3 1/3

b = -10/3

So the answer is

y = (- 1/3) x - 10/3 or

y = (-1 / 3)x - 3.3333 or

y = (-1/3 )x - (3 1/3)